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These questions Please Question 14 (2 points) Considering the previous question, the test statistic and P-value for this hypothesis test would be 0 test statistic

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These questions Please

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Question 14 (2 points) Considering the previous question, the test statistic and P-value for this hypothesis test would be 0 test statistic = 1.66 and P-value = between 0.1 and 0.2 0 test statistic = 1.01 and Pvalue = between 0.01 and 0.025 0 test statistic = 2.03 and P-value = between 0.025 and 0.05 O test statistic = -2.27 and P-value = between 0.05 and 0.1 Question 15 (1 point) Considering the previous question, because the P-value is greater or, we cannot conclude that no difference exists between the average ADM2304 exam grades for the Marketing and Finance introductory courses. Question 16 (2 points) Considering previously defined populations 1 and 2 in the question 12, which one of the following statements is true? 0 Because the 95% confidence interval does include zero, we cannot conclude that a difference exists between the average ADM2304 final exam grades for both Marketing and Finance fields. 0 Because the 95% confidence interval includes negative values, we can conclude that no difference exists between the average ADM2304 final exam grades for both Marketing and Finance fields. 0 Because the 95% confidence interval does not include zero, we can conclude that a difference exists between the average ADM2304 final exam grades for both Marketing and Finance fields. 0 Because the 95% confidence interval includes zero, we can conclude that a difference exists between the average ADM2304 final exam grades for both Marketing and Finance fields. Student 1 2 3 4 5 6 7 8 Marketing 82 86 74 93 90 76 87 100 Finance 76 91 70 79 96 70 85 81 Question 12 (2 points) If population 1 is defined as the ADM2304 exam score for student in Marketing and population 2 is defined as the ADM2304 exam score for student in Finance, the mean of the matched-pair difference is 12.5 5.0 O 14.8 8.3 Question 13 (2 points) Considering the populations 1 and 2 in the previous question, the degrees of freedom and critical value using a = 0. 05 for this hypothesis test would be O df = 6 and critical value = 2.998 O df = 7 and critical value =2.365 Of = 6 and critical value =1.771 O df = 7 and critical value =1.943

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