This code in C only outputs as 0.00000

What changes need to be made to have it output more than just 0.000000 as an answer without changing the structure of the code.

#include

float s_exp(float sub_exp, char op); // function declaration

char get_op(); // function declaration

float get_num(); // function declaration

float m_exp(float sub_exp, char op); // function declaration

int main(void)

{

char cont = 'Y';

while (cont == 'Y' || cont == 'y') //while result equals y, the main program runs

{

printf("Enter an arithmetic expression: ");

float result = s_exp(get_num(),get_op()); // call function for simple expression and set it equal to result

printf(" The result is %f ", result);

printf("Do you want to continue? Y/N ");

scanf("%c",&cont);

//to satisfy while loop at the beggining, enter y to continue

}

}

float s_exp(float sub_exp, char op)

{

// create an if else setup and if * or / are found for the operators call the m_exp function because those take higher precidence in a bedmas calculation

if (op == ' ')

return sub_exp;

else if (op == '+')

return s_exp(sub_exp + get_num(), get_op());

else if (op == '-')

return s_exp(sub_exp - get_num(), get_op());

else if (op == '*')

return m_exp(sub_exp * get_num(), get_op());

else if (op == '/')

return m_exp(sub_exp / get_num(), get_op());

else

//if nothing is found thats / * + or - the operator is invalid and exit the program

{

printf("This expression is invalid. ");

return 0;

}

}

//m_exp takes higher precidence for the * or / operators. store those operators and return to sub_exp when a space, + or - is found. this is set through else if.

float m_exp(float sub_exp, char op) {

float f1;

char ch1;

if (op == ' ')

return sub_exp;

else if (op == '+')

return s_exp(sub_exp + get_num(), get_op());

else if (op == '-')

return s_exp(sub_exp - get_num(), get_op());

else if (op == '*'){

f1 =get_num();

ch1 = get_op();

}

else if (op == '/'){

f1 = get_num();

ch1 = get_op();

}

else

{

printf("This expression is invalid. ");

return 0;

}

return m_exp(f1, ch1);

}

// this if for assistance with the first two functions, this gathers the next operator in the expression.

char get_op()

{

char op = ' ';

while (op == ' ')

scanf("%c", &op);

return op;

}

// this if for assistance with the first two functions, this gathers the next number in the expression.

float get_num()

{

float num;

scanf("%f", &num);

return num;

}