Question
This demonstration problem shows how to work with a (discrete) probability distribution table (PDT). You have been given the following PDT random variable kk probability
This demonstration problem shows how to work with a (discrete) probability distribution table (PDT). You have been given the following PDT
random variable kk | probability P(X=k)P(X=k) |
---|---|
0 | 14% |
1 | 21% |
2 | 19% |
3 | 17% |
4 | 16% |
5 | 13% |
You would like to find the probaiblity of obtaining the values between (and including) 3 and 5P(3X5)P(3X5)This would be found by breaking the event into smaller disjoint events:P(3X5)=P(X=3)+P(X=4)+P(X=5)P(3X5)=P(X=3)+P(X=4)+P(X=5)Looking up these values in the table, we haveP(3X5)=17%+16%+13%P(3X5)=17%+16%+13%Thus, the probability of obtaining a value between 3 and 5 isP(3X5)=46%P(3X5)=46%. Practice Problem Find the probability that the random variable is even: P(X is even)=P(X is even)= % Enter answer as a percentage, but do not type "%" at the end.
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