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This is a MATLAB question. A number of BME students have decided to participate in a Polar Bear Plunge into Summit Lake After realizing how

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This is a MATLAB question.

A number of BME students have decided to participate in a "Polar Bear Plunge into Summit Lake After realizing how cold it was going to be, they decide to develop a MATLAB program to estimate the beat loss. Since they don't anticipate spending substantial time in the water, they are only interested in l-minute exposures. Further, in this short period, they don't anticipate a significant decrease in the body's surface temperature of 35C (the body's core temperature is-370- However, they assumed that the water fully covers the surface to the body. In general, convective heat loss from a human to water is described by the equation Q=K4(T-1) where: heat loss [=] kcal/hr E = heat transfer coefficiental kcal 4=surface area of the student (=] m T. = surface temperature of the student (=1 C T = temperature of the water assuming moving water (= 1 C The area of a student is described by the equation: 4= 71.8 .725 where: W = student's body weight [=] kg (note: 1 lb=0.45359 kg) H = student's height [=] m (note: 1"=0.0254 m) For this problem: 57.6 54.0 57.6 Water Temp PC OCTC8 8>T 27 27T 33C (91F) it isn't a polar bear plunge). The final value should then be displayed on the console d) Write an m-file to plot heat loss vs. temperature. You may hard code the data for x and y into your program (1 point each) A number of BME students have decided to participate in a "Polar Bear Plunge into Summit Lake After realizing how cold it was going to be, they decide to develop a MATLAB program to estimate the beat loss. Since they don't anticipate spending substantial time in the water, they are only interested in l-minute exposures. Further, in this short period, they don't anticipate a significant decrease in the body's surface temperature of 35C (the body's core temperature is-370- However, they assumed that the water fully covers the surface to the body. In general, convective heat loss from a human to water is described by the equation Q=K4(T-1) where: heat loss [=] kcal/hr E = heat transfer coefficiental kcal 4=surface area of the student (=] m T. = surface temperature of the student (=1 C T = temperature of the water assuming moving water (= 1 C The area of a student is described by the equation: 4= 71.8 .725 where: W = student's body weight [=] kg (note: 1 lb=0.45359 kg) H = student's height [=] m (note: 1"=0.0254 m) For this problem: 57.6 54.0 57.6 Water Temp PC OCTC8 8>T 27 27T 33C (91F) it isn't a polar bear plunge). The final value should then be displayed on the console d) Write an m-file to plot heat loss vs. temperature. You may hard code the data for x and y into your program (1 point each)

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