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This is for my calculus class, any help would be appreciatd! 0 Question 7 I14 0:1 pt '0 5 8 3 (9 Details Consider the
This is for my calculus class, any help would be appreciatd!
0 Question 7 I14 0:1 pt '0 5 8 3 (9 Details Consider the function f(:l':) = :32. It can be shown that the derivative of f is f[:c) = 2:121. Find L(:L'), the equation of the line tangent to the graph of f at a = 2. Llw) = l Question Help: I3 Message instructor Submit Question Jump to Answer 0 Question 8 |:./ on pt '0 5 8 3 (9 Details The point [13, 7) lies on a differentiable function m). The tangent line to f($) at a: = 13 also goes through the point (9, 41). What is f'(13) ? f'(13)=l lStep by Step Solution
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