THIS IS FOR STATS PLEASE ANSWER CLREALY AND DIGATALLY

Q7:

Assume that random guesses are made for 2 multiplechoice questions on a test with 2 choices for each question, so that there are n = 2 trials, each with probability of success (correct) given by p = 0.50. Find the probability of no correct answers. 5' Click on the icon to View the binomial probability table. The probability of no correct answers is D. (Round to three decimal places as needed.) Reference Binomial Probabilities P n X .01 .05 .10 .20 .30 40 .50 60 .70 80 90 .95 99 X No O 980 902 810 .640 490 360 250 .160 .090 040 .010 002 0+ - O .020 .095 .180 .320 .420 .480 .500 .480 .420 .320 .180 .095 .020 N - 0+ .002 010 .040 .090 160 250 360 490 640 .810 .902 .980 NO 3 O .970 857 729 .512 .343 .216 . 125 .064 .027 .008 .001 0+ 0+ 0 029 .135 .243 .384 441 432 .375 .288 .189 .096 .027 007 0+ N - 0+ .007 027 .096 .189 .288 .375 432 441 .384 .243 135 .029 N Co 0+ 0+ .001 .008 .027 064 .125 216 343 .512 .729 857 .970 4 O 961 .815 656 .410 240 .130 062 026 .008 .002 0+ 0+ 0+ O 039 .171 .292 .410 412 .346 .250 154 .076 .026 .004 0+ 0+ .001 .014 .049 .154 .265 346 .375 .346 .265 .154 .049 .014 .001 No co N 0+ 0+ .004 026 076 .154 .250 346 412 .410 .292 171 039 0+ 0+ 0+ .002 .008 .026 062 130 240 410 .656 .815 .961 A O .951 .774 .590 328 .168 078 031 010 .002 +0 0+ 0+ 0+ O .048 .204 328 .410 .360 259 . 156 .077 .028 .006 0+ 0+ 0+ N .001 021 .073 205 .309 .346 312 230 .132 .051 .008 001 0+ No Co 0+ .001 .008 .051 .132 .230 .312 .346 .309 .205 .073 .021 .001 Co me 900Assume that when human resource managers are randomly selected, 46% sayjob applicants should follow up within two weeks. If 13 human resource managers are randomly selected, find the probability that fewer than 4 of them say job applicants should follow up within two weeks. The probability is D. (Round to four decimal places as needed.) Based on a poll, among adults who regret getting tattoos, 21% say that they were too young when they got their tattoos. Assume that ten adults who regret getting tattoos are randomly selected, and nd the indicated probability. Complete parts (a) through (d) below. (3 a. Find the probability that none of the selected adults say that they were too young to get tattoos. D (Round to four decimal places as needed.) b. Find the probability that exactly one of the selected adults says that he or she was too young to get tattoos. '1 (Round to four decimal places as needed.) c. Find the probability that the number of selected adults saying they were too young is 0 or 1. D (Round to four decimal places as needed.) d. if we randomly select ten adults, is 1 a significantly low number who say that they were too young to get tattoos? El because the probability that |:| of the selected adults say that they were too young is |:| 0.05. Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 35 couples. Complete parts (a) through (c) below. {I} a. Find the mean and the standard deviation for the numbers of girls in groups of 35 births. The value of the mean is p = E. (Type an integer or a decimal. Do not round.) The value of the standard deviation is o = D. (Round to one decimal place as needed.) b. Use the range rule of thumb to find the values separating results that are significantly low or signicantly high. Values of D girls or fewer are significantly low. (Round to one decimal place as needed.) Values of D girls or greater are significantly high. (Round to one decimal place as needed.) C. Is the result of 33 girls a result that is significantly high? What does it suggest about the effectiveness of the method? The result signicantly high, because 33 girls is |:| |:| girls. A result of 33 girls would suggest that the method (Round to one decimal place as needed.)