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This is my assignment: Find remainder of 98! when divided by101. Wilson Theorem (101 - 1)! = 100! = -1 (mod 101) (101-2)! = 99!=
This is my assignment: Find remainder of 98! when divided by101. Wilson Theorem (101 - 1)! = 100! = -1 (mod 101) (101-2)! = 99!= -2 (mod 101) (101 - 3)! = 98 ! = -3 (mod 101) We know that 100! =-1 and 100 * 99 * 98! = -1 ****QUESTION**** Can you explain (below)why 100 = -1 and 99=-2? I know it is inverse, but don't get it.Thanks! (-1) * (-2) * 98! = -1
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