This is pretty many, but i hope you can help me out.. BIG THANKS IN ADVANCE!

A. Find the equation of the parabola using the indicated conditions and sketch the graph. 1. V( 0. 0) and F (- 3. 0) 4. Vertex at origin, opens upward and one of the end points of the latus rectum ( 3. 4) 7. Vertex (-3. 2) and focus (-3, 5) 8. The parabola with vertex at (-6 , 0) and opens downward shifted 3 units to the left and 2 units upward. Its length of the latus rectus is found to be 20 units. Derive its new equation. 2. Directrix line equation y - 7 = 0. vertex at the origin and opens upward. 5. End points of latus rectum are at 9. Focus (5. - 4) and the directrix (-8. - 4) and (8, - 4) and vertex at the equation is x - 9 -0 origin 6. Vertex (1. 4), passing through 10. Vertex ( - 4, ) and Length of latus (4 , 2) and axis parallel to x-axis rectum 8 units. 3. Focus (0, 5) and latus rectum length of 16 units