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This is statistics course and I need help with those questions. This is sampling distribution unit. D Question 7 20 pts 7. Suppose two species

This is statistics course and I need help with those questions. This is sampling distribution unit.

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D Question 7 20 pts 7. Suppose two species of bears are being studied and we are interested in comparing a sample of 15 bears of each species. In a research journal, you discover the mean weight of American black bears is about/ M, = 240 pounds with a standard deviation of 25 points and the mean weight of pandas is known to be approximately / M2 = 190 pounds with a standard deviation of 19 pounds. Which of the following statements must be true? I. MM1-M2 = 50 I1. OM1-M2 = 252 + 192 15 15 ~ 8.1 Ill. There is approximately a 68% chance that the mean weight of the 15 black bears is greater than the mean weight of the 15 pandas by 41.9 pounds to 58.1 pounds O I only O Ill only O I and Il only O Il and Ill only O I, II, and IllD Question 6 10 pts 6. Consider the distribution below. mean= 8 08 Parent population (can be changed with the mouse) median= Parent sd= 6.22 skews 0.83 0.06 Distribution kurtosis= Can the distribution above be used to simulate both distributions below? $295 6915 5532 - 1st 4149 2766 1383 TITTITTITTS 29964 - 24970 19976 - 2nd 14982 - 4004 Choose the best response and explanation. O No. The first distribution is not likely because it is too similar to the shape of the parent distribution. No. The second distribution is not likely because the parent population is not normal. Yes. The first distribution is skewed because it likely had a large sample size. The second sampling distribution is more normal and has a more narrow spread because it likely had a sample size near 50. Yes. The first distribution is skewed because it likely had a small sample size. The second sampling distribution is more normal and has a more narrow spread because it likely had a sample size near 30.D Question 3 10 pts 3. Consider a skewed right distribution. Which of these best describes the shape of the sampling distribution when n = 5? O There is no way to predict the shape without conducting a simulation. O Skewed right, but less severe than the population from which the samples were taken. O Skewed right, but more severe than the population from which the samples were taken. O Approximately normal due to the Central Limit Theorem. O Uniform because the Central Limit Theorem does not apply until n > 30. D Question 4 10 pts 4. Consider a skewed right distribution. Which of these best describes the shape of the sampling distribution when n = 100? O There is no way to predict the shape without conducting a simulation. O Skewed right, but less severe than the population from which the samples were taken. O Skewed right, but more severe than the population from which the samples were taken. O Approximately normal due to the Central Limit Theorem. O Uniform because of the Central Limit Theorem.Question 2 10 pts 2. Suppose it is known that the mean number of runs scored by the White Sox last season is 3.8, with a standard deviation of 1.2 and the mean number of runs scored by the Astros last season is 4.1, with a standard deviation of 1.6. Suppose you watched 30 games from each team last season and calculated the mean for the games you watched for each team. Which of these can be used to approximate the probability that out of the games watched, the mean number of runs scored for the Astros was at least 1 run higher than the White Sox? There may be more than one answer so select all that apply. C] normalcdf(-9999, -1, -0.3, 0.365) [:I normalcde-9999, -1.918, 0,1) [:I normalcdf[1.918, 9999, O, 1) [:I normalcdl, 9999, 0.3, 0.365} Question 1 10 pts 1. By combining over 100 studies totaling over 1.7 million participants, it is found that 11% of men and 9% of women are left-handed. Suppose you were to conduct your own random survey of 100 men and 100 women. What is the probability that your survey would nd a higher proportion of left-handedness in men than in women? 0 0.41 O 0.46 O 0.65 O 0.68 O 0.71 D Question 5 10 pts 5. True or false: The following distribution of 100,000 sample means, each with a sample size of 5, Reps= 100000 Distribution of Means, N=$ mean= 16 01 $640 - Mean median= 16.00 7200 - N=5 . sd= 4.26 $760 - skew= 0.01 4320 - Fit normal kurtosis= -0.23 1440 could come from a uniform population such as the one below. mean= 16.00 Parent population (can be changed with the mouse) median= 16.00 sd= 952 skew= 0.00 kurtosis= 1.20 O True. O False, because n is not at least 30. O False, because the sampling distribution of a uniform distribution must be approximately uniform.Question 8 20 pts 8. Suppose population A has a mean of 122 shekels and a standard deviation of 6. Population B has a mean of 117 shekels and a standard deviation of 8. You sample 18 scores from population A and 32 scores from population B. (a) What is the mean of the sampling distribution of the difference between means (Pop A - Pop B)? [ Select ] (b) What is the standard deviation of the sampling distribution of the difference between means (Pop A - Pop B)? [ Select ] Select 1.1 1.4 (c) What is the probability that you 2.0 mean of at least 9 shekels more than your sample from population B? [ Select ] This question is adapted from Online Statistics Education: A Multimedia Course of Study (http://onlinestatbook.com/). Project Leader: David M. Lane . Rice University.Question 8 20 pts 8. Suppose population A has a mean of 122 shekels and a standard deviation of 6. Population B has a mean of 117 shekels and a standard deviation of 8. You sample 18 scores from population A and 32 scores from population B. (a) What is the mean of the sampling distribution of the difference between means (Pop A - Pop B)? [ Select ] (b) What is the standard deviation of the sampling distribution of the difference between means (Pop A - Pop B)? [ Select ] (c) What is the probability that your sample from population A has a mean of at least 9 shekels more than your sample from population B? [ Select ] Select ] This question is adapted from Online Statistics Education: AN 0.072 0.023 Project Leader: David M. Lane . Rice University. 0.500Question 8 20 pts 8. Suppose population A has a mean of 122 shekels and a standard deviation of 6. Population B has a mean of 117 shekels and a standard deviation of 8. You sample 18 scores from population A and 32 scores from population B. (a) What is the mean of the sampling distribution of the difference between means (Pop A - Pop B)? [ Select ] Select -5 (b) What is the standard deviation 2.5 difference between means (Pop A - Pop B)? [ Select ] (c) What is the probability that your sample from population A has a mean of at least 9 shekels more than your sample from population B? [ Select ] This question is adapted from Online Statistics Education: A Multimedia Course of Study (http:/onlinestatbook.com/). Project Leader: David M. Lane , Rice University

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