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This is the question Q22 Let D be the trapezoid with vertices (0, 5), (6, 5), (2, 0) and (4, 0). Let g(x, y) be

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Q22 Let D be the trapezoid with vertices (0, 5), (6, 5), (2, 0) and (4, 0). Let g(x, y) be some continuous function. a Sketch D and set up the bounds of integration for JJ, g(x, y) dA such that you obtain one integral (not a sum or difference of integrals). b If you wanted to use an antisymmetry argument to show that ,g(x, y) dA = 0 what would need to be true about g(a, y)? Express your answer as a formula.Section 6.2 Q22 a D does not have a single bottom function, but does have single right and left functions. To write it as one integral we need to use the order dady. g(x, y) dady * =3 (x,y) (6-x.y) By +2 y+ 4 b D is symmetric about a = 3. Checking pairs of reflected points, we see they have the same y coordinates, but that their r coordinates always sum to 6. Thus ry(x, y) = (6 -x, y). In order to use antisymmetry, we would need that g(x, y) = -9(6 - x, y)

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