This lab explores objects moving with either a constant velocity or a constant acceleration and involves the use of graphs and equations to analyze the motion of that object. - Preparation (5 minutes) Activity 1: Graph and interpret motion data of a moving object (15 minutes} Activity 2: Calculate the velocity of a moving object (20 minutes) Activity 3: Graph the motion of an object traveling under constant acceleration (20 minutes) Activity 4: Predict the time for a steel sphere to roll down an incline (10 minutes) Activity 5: Demonstrate that a sphere rolling down the incline is moving under constant acceleration (20 minutes Note: Additional time (one to two hours} will be needed to complete the lab report following the activities. Read through the overview, objectives, and background information provided in the Kinematics Investigation Manual. Review what materials will be needed (p. 8). the Safety procedures (p. 9), and acquire the needed materials that are not supplied. Prepare for the activity by reading through the entire set of instructions prior to starting. The instructions are found on pages 10-28. Set out all materials necessary for this activity that are listed in the Materials section (p. 8) in preparation to perform the activity. Make sure that you have set aside the necessary time to perform the activity. This is listed in the Time Requirements section (p. 3). Perform the activities, following the instructions carefully (p. 1128). Allow additional time (one to two hours) to complete the lab report and upload the lab report document when nished. Use the P_hy-150 M2 Kinematics Lab Repo_rt template to complete the lab assignment. Supporting Materials This How to - Submit an Assignment tutorial from SNHU Service Now may be helpful if you need guidance when uploading your document. You may use any method you like to create graphs for your lab report, including drawing by hand. The Create an Excel chart in Word tutorial may _ be helpful if you are new to creating graphs. I ' Distance vs Time of a Moving Object. Position vs Time 80 70 Position(m) 10 0 0 10 20 30 40 50 60 Time(s)Question 9: What does the sign of the slope in question 8 represent in terms of the motion of the train? 0 Negative sign of slope in Q8 represents the change in direction of the object (negative velocity) Question 10: 1What is the average velocitgtr of the train during the interval t= Us to t = 505? 0 Average velocity = v ={52sl]_-"{t3t1} = (550)" {500} = 55550 = 1.1 111-"s Question ll: Does the train's average velocity during the interval t= Us to t = 50 s provide a complete picture of the train's motion during this time? 0 No, here the average velocit},r is positive. But m some time htterssal the body is at rest and at some time intenial the body is changing its direction. Questions for Activity 1 Question 1: 1What is the average speed of the train during the time interval from 0 s to 10' s? 0 Average speed = Total distance -"total time = 40.:"10 = 4 nL-'s Question 2: Using the equation: 12: 323 ltZtl, calculate the average speed of the train as it moves from position X = 50111 to x = 60m. 0 v =(s251}.-"'(t2t1] = {_6050}.-" [3015) = 10:15 = 0.6? nL-'s Question 3: 'that does the slope of the line during each time interval represent? 0 In a position vs time graph, the slope represents the velocity during each time interval. Question 4: From time t = 35 5 until t = 45 5= the train is located at the same position. 'What is slope of the line while the train is stationary? 0 Slope = 0 m.='s, when train is stationary Question 5: Calculate the average speed of the train as it moves from position X = 70111 to x = 55m. What does the sign of the average velocity during this time interval represent? . v =(x2X1lr'l'E3t1} = {sstm {5035} = 45:15 = l 1n.-"s Question 6: What is the displacement of the train from time t = US until t = 505? 0 Negative sign represents that the body changed its direction. Question 7": 'that is the total distance traveled by the train from time t = Os until t = 50s? 0 Total distance = TO + 15 = 85 m Question 8. What is the slope of the line during the time interval t = 45 to t = 50? 0 Slope = {SST0).-" (5045) = l.-"5 = 3 m-"s Activity 1: Graph and interpret motion data of a moving object Time (s) Position(m) O 5 20 10 40 15 50 20 55 30 60 35 70 40 70 45 70 50 55 Distance vs Time of a Moving Object.Activity 2. Calculate the velocity of a moving object. Activity 2. Table 1 Time (s) Displacement (m)* 0.00 0.25 0.50 0.75 1.00 1.25 1.50 1.75 2.00 *Note that 0.25 m = 25 cm Insert a graph of Table 1 here. Include a chart title, axes titles and units. Activity 2. Table 2 Time (s) Velocity (m/s) 2 3 4 5 Co