This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come bad to the skipped part. Tutorial Exercise Consider the circuit shown in the figure below. (R = 11.0 0.) 25.0 V 10.0 0 10.0 0 5.00 02 5.00 0 A (a) Find the current in the 11.0 0 resistor. (b) Find the potential difference between points a and b. Part 1 of 7 - Conceptualize The current that flows from b to a around the outer loop through R and the 5-Q resistor is on the order of fractions of amps. Point b will be at higher potential than point a by several volts Part 2 of 7 - Categorize We must analyze the entire circuit in order to find the current in any one resistor. This circuit has a single power supply so we can reduce the circuit into equivalent circuits with equivalent resistances for series and parallel combinations. Part 3 of 7 - Analyze If we turn the diagram of the original figure on its side and shorten some of the wires, we see that it is the same as diagram (i) in the figure below. Resistances denoted by R.;, R;; ;, and Ry in the diagrams below refer to the equivalent resistances in these circuits. Since diagram (1) is merely a rotation of the original figure, the unknown resistance here is denoted by R as in the original figure. The resistor R and the 5-0 resistor are in series, so the first reduction into an equivalent circuit is shown in diagram (ii). For the equivalent resistance in this circuit, we have R;; = 5.00 0 + R = 25 V 25 V 25 V 25 V 210 0 210 0 10 ( 5.0 0 5.0 0 $10 0 5.0 03 10 0 (i) (ii (iv) In diagram (ii), since the 10.0-0, the 5.00-0, and resistor R,, are in parallel, we compute the equivalent resistance as 1/10.0 0) + 1/5.00 0) + 1/ 10