This question is from past VCE exams that already have full solutions posted on the official VCAA website, hence I am not violating the Honor Code. Please provide me with more in depth solutions as I still do not understand it, thank you :)

Question 6 - VCAA 2013 Exam 2 Question 4 7 marks 16-2:2 4 is shown below. Part of the graph of a function g: R > R, g(x) = y a. Points 3 and C are the positive xintercept and y-intercept of the graph of g, respectively, as shown in the diagram above. The tangent to the graph of g at the point A is parallel to the line segment BC. i. Find the equation of the tangent to the graph of g at the point A. 2 marks b. Let Q be a point on the graph of y = g(x). Find the positive value of the xcoordinate of Q, for which the distance 0Q is a minimum and nd the minimum distance. 3 marks The tangent to the graph of g at a point P has a negative gradient and intersects the y-axis at point D(0, k), where 5 S k S 8. c. Find the gradient of the tangent in terms of k. END OF REVISION SHEET 1 TA TEST Zmarks