Three activities are candidates for crashing on a project network for a large computer installation (all are, of course, critical). Activity details are in the following table: Normal Activity Time (days) A B C 7 4 11 Crash Time (days) 6 2 9 The crash cost per period is: Normal Cost $4,500 $1,500 $4,600 Crash cost per period = 4 Total Cost with Crashing Immediate Predecessor(s) a) Activity that should be crashed first to reduce the project duration by 1 day is A b) Activity that should be crashed next to reduce the project duration by one additional day is B c) Total cost of crashing the project by 2 days = $2400). (Enter your response as an integer.) > That's incorrect. $5,000 $3,400 $7,000 A B Crash Cost - Normal Cost Normal Time - Crash Time To find the total cost of crashing the project, multiply the crash cost per period for each activity by the number of periods that that activity is crashed by. Then, sum these values for all applicable activities. X

Three activities are candidates for crashing on a project network for a large computer installation (all are, of course critical) Activity details are in the following table a) Activity that should be crashed first to reduce the project duration by 1 day is b) Activity that should be crashed next to reduce the project duration by one additional day is c) Total cost of crashina the proiect bv 2 davs =$2400. (Enter vour response as an inteqer.) \& That's incorrect. The crash cost per period is Crashcostperperiod=NormalTimeCrashTimeCrashCostNormalCost To find the total cost of crashing the project, multiply the crash cost per period for each activity by the number of periods that that activity is crashed by. Then, sum these values for all applicable activities