Three students, Adam, Bailey and Carlos, are tugging on a multi-colored hoop (as in the figure). Despite the three forces, the tire does not move. Adam pulls with a force F of magnitude 208 N, and Carlos pulls with a force Fc of magnitude 188 N. Angle AB = 140 degrees. Note that the direction of Fc is not given. What is the magnitude of Bailey's force? ||FB = [27.17 N Hint: The direction of Fc can be determined by balancing forces in the x direction (since FB is purely along the y-axis). Given the magnitudes of FA and Fc, and angle AB you can set FAZ = FCI and determine the angle of Fc. You know the sum of y components of FA and Fc have to cancel FB. Adam 0AB Bailey Carlos Fa 4 208 N Fc = 1880 OAB = 140 = FFA+F+ 2 FAFB Cos AB 1882 = 208 + FB + 2 (208 F6) Cos (140) . 35344 43264 + F33 + 318.67 FB FB-31.67 Fb + 43264 = O -(-318.67) (-318.67) - (4x1 x WB 7920) -318.67 101,550.57 - 31680 2 318 6.67-769870.57 2 31.6726433 2 54.34 2 =27117