Three types of fertilizer were used on132identical plots of maize. Each plot was harvested and the yield (in kg) was recorded.Type of FertilizerYield (kg)IIIIIIRow Total0-2.9161015413.0-5.9142111466.0-8.916191045Column Total465036132Use a 5% level of significance to test the hypothesis that type of fertilizer and yield of maize are independent. Interpret the results.

What is the level of significance?

State the null and alternate hypotheses.

H₀: Yield and fertilizer type are not independent

H₁: Yield and fertilizer type are independent.

H₀: Yield and fertilizer type are independent

H₁: Yield and fertilizer type are not independent.

Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)

What are the degrees of freedom?

Find or estimate theP-value of the sample test statistic.

P-value > 0.100

0.050 <P-value < 0.100

0.025 <P-value < 0.050

0.010 <P-value < 0.025

0.005 <P-value < 0.010

P-value < 0.005

Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis of independence?

Since theP-value >, we fail to reject the null hypothesis.

Since theP-value >, we reject the null hypothesis.

Since theP-value, we reject the null hypothesis.

Since theP-value, we fail to reject the null hypothesis.

(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, there is insufficient evidence to conclude that yield and fertilizer type are not independent.

At the 5% level of significance, there is sufficient evidence to conclude that yield and fertilizer type are not independent.