Three wires sit at the corners of a square, all carrying currents of 2 amps into the page as shown in Figure 12.8. Calculate the magnitude of the magnetic field at the other corner of the square, point P, if the length of each side of the square is 1 cm. 12 41 13 The magnetic field in the x-direction has contributions from wire 3 and the x-component of wire 2: Bnet x = -4 x 10-5T- 2.83 x 10-5T cos(45) = -6 x 10-5 T. The y-component is similarly the contributions from wire 1 and the y-component of wire 2: Bnet =-4 x 10-5T- 2.83 x 10-5T sin(45) = 6 10T. y Therefore, the net magnetic field is the resultant of these two components: Bnet Bnet Bnet = B VDnet x + B "net y = (-6 10-5T) + (-6 10-5T) = 8 x 10-5 T.