Question
Timothy decides to work out and goes for a 6 mile bicycle ride. But Timothy isn't very fit, so he will have to stop every
Timothy decides to work out and goes for a 6 mile bicycle ride. But Timothy isn't very fit, so he will have to stop every now and then to take a breather. His breaks will vary depending quickly he catches his breath. Let us model the number of breaks Timothy has during one of his 6 mile rides with a random variable X that has a Poisson distribution of = 1. Bob, Timothy's brother, who is also quite unfit, also rides the same path, and also stops when he is tired. The duration of his stops is modeled with a random variable Y with a mean of 0.9 minutes and variance of 1. The amount of times Bob pauses his ride for a breather is also a Poisson random variable X of = 1 and is independent of the length of the stops. If Bob doesn't take any pauses in his ride, he will travel 6 miles within 45 minutes.
- If Bob stops 3 times for a breather, compute the expected length of Bob's ride by conditioning.
- Again, if Bob stops 3 times for a breather, compute the variance of the length of Bob's ride by conditioning.
- Compute the expected length of one of Bob's runs, including stops. You should approach this by conditioning on random variable X.
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