1. To be accepted into MENSA, the high IQ society, persons must score in the top 2% of a recognized IQ test, such as the Stanford-Binet. If the mean score on the Stanford-Binet is 100 and the standard deviation is 16, which of the following three IQ scores on the test would qualify for acceptance into MENSA: 115, 125, and 135? Explain, showing your work. (Round at each stage of any calculation to the second decimal place.)

I found Z score for all 3:

115 Z= .9375

125 Z= 1.5625

135 Z= 2.1875

How do I show work for what the top 2% without excel?Would it be... z=[(x)/] 2= [(x-100)/16] 2(6) = (x-100) 32+100=x 132=x