To check whether a column contains all numbers from 1 to 4 in a puzzle vector, we will do the following:1. Create a stack called numbers, which contains all numbers from 1 to 4 2. Initialise a variable k to be 1 3. For the element k in a column, store the number in that element to a variable called value and call Search- Stack(numbers, value) 4. If the function returns FALSE, then we should return FALSE as a number appears twice or not at all in the stack 5. If the function returns the stack, increase the value of k by one and go to step 3 6. If after checking all elements in the column, SearchStack has not returned FALSE, we return TRUE

In the next task you will need to complete a function that carries out this algorithm for column j of the input puzzle.

ANSWERS HAVE TO BE IN PSEUDOCODE, NO OTHER FORM. Task 5: Complete the following function: function CheckColumn(puzzle, j) ... end function

This function will take the vector puzzle (as produced by MakeVector) as an input parameter and check that column j contains all numbers from 1 to 4: if it does contain all numbers from 1 to 4, it should return TRUE, otherwise it should return FALSE. The procedure you should use is the one outlined above. To get full marks you need to call SearchStack(stack, item).

Once we have a method for checking one column, we can use the following function to check all columns: function ColChecks(puzzle) for 1 j 4 do if CheckColumn(puzzle, j) = FALSE then return FALSE end if end for return TRUE end function This will be useful later on.

Do answer the task after seeing the MakeVector and SearchStack function, in the link below.

https://www.chegg.com/homework-help/questions-and-answers/answer-pseudocode-coding-explanation-necessary-pseudocode-checking-pseudoku-conditions-nex-q90836254?trackid=xax_g1GQ