To compute the azimuth from north of line CD for Problems 7.10 and 7.11, you can use the following steps: For Problem 7.10: 1. Start with the azimuth of AB, which is 1012632. 2. Add the angle to the right, ABC, which is 505426. 3. Subtract the angle to the right, BCD, which is 3836'38". So, the azimuth from north of line CD for Problem 7.10 is: 1012632 +505426 - 383638 = 1134420. For Problem 7.11: 1. Start with the bearing of AB, which is 52308'24". Convert this to an azimuth by adding 180, which gives 20308'24". 2. Add the angle to the right, ABC, which is 982006. 3. Subtract the angle to the right, BCD, which is 1042108. So, the azimuth from north of line CD for Problem 7.11 is: 2030824 + 982006 - 1042108 = 19607'22". Please note that in Problem 7.12, the provided information appears to be incomplete or formatted incorrectly. If you can provide more details or clarify the data, I'd be happy to assist with that as well.