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To get from Berkeley to the San Francisco airport (SFO) one can either take a shuttle van or drive. Either way, one must cross the

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To get from Berkeley to the San Francisco airport (SFO) one can either take a shuttle van or drive. Either way, one must cross the San Francisco Bay Bridge. The shuttle van drops its passengers at the airport departure terminal. If one drives, he or she must park in a lot near the airport, then take a parking shuttle from the parking lot to the airport departure terminal. There is a 60% chance that the Bay Bridge will be congested with traffic. If it is, it takes 1.3 hours to drive to the parking lot. It not, it takes 40 minutes to drive to the parking lot. The parking shuttle runs every 10 minutes and takes 10 minutes to get to the airport departure terminal trom the parking lot. Suppose it is equally likely that one must wait 0, 1, 2, ..., or 9 minutes for the parking shuttle once getting to the parking lot, and that the amount 01 time one must wait is independent of the amount of time it takes to drive to the parking lot from Berkeley. If one takes the shuttle van from Berkeley directly to the airport, it will take an hour, plus 10 minutes per stop for other passengers. Suppose that it is equally likely that the shuttle van will make 0, 1, 2, or 3 stops to pick up other passengers. The shuttle van can take the carpool lane; assume that the time it takes the shuttle van to go from Berkeley to the airport is not affected by trafc on the bridge. The chance it takes less than one hour to get to the airport by driving and taking the parking shuttle is (Q7) E The chance it takes more than 91 minutes to get to the airport by driving and taking the parking shuttle is (QB) The chance it takes more than 91 minutes to get to the airport taking the shuttle van directly from Berkeley to the airport is (09) Suppose John takes the shuttle van directly from Berkeley to the airport, and Jane drives from Berkeley and takes the parking shuttle. They leave at the same time, and their travel times are independent. The chance that John gets to the airport before Jane is (010)

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