To get the antiderivative of 2x2. tan ( 4x3 ) using substitution method (to be applied only once), we let u = O tan(4x3) O 4x 3 O x 3 O 2x 2 O Substitution method will not work.(I cannot give you the graph here as it may give you a clue on how to evaluate the definite integral. For a clue though, you can simplify first the integrand using a trigonometric identity.) 1/4 Evaluate: (1 + tan2x) dx(Use DESMOS or any online graphing application here.) Consider the closed region bounded by the graphs of y =2x- -7x+7, y=0.875 and the y-axis. If one wishes to find the volume of the solid that is generated by revolving such region about the y-axis using the DISK METHOD, what must be the upper bound of the definite integral that will give the volume?/ (52x ) 2 ( 2 In 5 ) dix is O 521 +C 4 O 524 +C 2 O 5' 4.x +C 4 O 5' 1.X +C 2 O No correct option was presented here for this item