To illustrate that the length of a smooth space curve does not depend on the parameterization used to compute it, calculate the length of one turn of the helix with the following parameterizations. a. r(t) = (cos 4t)i + (sin 4t)j + 4tk, Ost= 2 b. r(t) = cos (2) ]it [sin (2)1+ 2K. Ost54x 1 = 27 c. r(t) = (cost)i - (sin t)j - tk, - 2ists0 Note that the helix shown to the right is just one example of such a helix, and does not exactly correspond to the parametrizations in parts a, b, or c. 1,0.01=0 a. L =(Type an exact answer, using it as needed.) b. L = (Type an exact answer, using it as needed.) C. L = (Type an exact answer, using it as needed.)