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To improve the odds of successfully transmitting a multibit word, we designate the last bit as the parity bit. That is, if we declare that

To improve the odds of successfully transmitting a multibit word, we designate the last bit as the parity bit. That is, if we declare that our words are even parity, then any 8-bit sequence that we transmit will have an even number of 1s. Likewise, odd parity means that out of 8 bits, we have an odd number of 1s. The parity bit is set to 0 or 1 as needed to achieve the specified parity. Using this parity bit, what is the probability of successful transmission now? What is the trade-off?

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