To represent the area of A with an integral, it can easily be written as (100 " (7 - (07 0?0?@?@?0?0 - 7273 8 70 018336 - 78785x) 070? The integral can be split through linearity to represent [ @ / 8366. - ?078103x Next through using substitution it can be represented as u = .04785x, du/dx = .04785, dx = du/.04785 or dx = 20.8986du a 20.8986094785x So * - (.8366) 20.8986104785x a - 17.4838094785x + 4 is the solved integral 2 The Definite integral is defined as - 17.483894785x) |(x=100) - (* - 17.48380.04785x)|(x=0) 2 2 So ( 1002 - 17.483804785(100)) _ (" - 17.4838504785(9)) a 2907.1653 + 17.4838 = 2924.6491