To supply the city of Oz, water must be pumped from a once-mighty river to the top of a small mountain. This problem asks you to calculate the head and power required for pumping. It is conventional in water hydraulics to express the needed pressure in terms of the total head of water, which is due to the elevation change (h), plus the head loss (hloss) due to the friction of moving water in a pipe. The pressure created by the height h of a column of water due to gravity P = , where is the mass density of water and g is the gravitational constant. If water moves with velocity V through a pipe of diameter D and of length L, the head loss = 2f LV^2/DG where f is a dimensionless "friction factor" that accounts for the viscosity of the water and nonlaminar flow within the pipe. Gravity does not contribute, but the constant g appears in order to convert the pressure drop into the form of a head. Quantities needed in the problem (rounded off for simplicity): The elevation changes from 100 m at the river to 1.1 km in Oz The pipe L