Toyota Camry Hybrids that get an average of =52 MPG. Supposed the standard deviation is =2.46 MPG. Assuming mileage is normally distributed what is the probability that a randomly selected Camry gets less than 51 MPG? P(X<51)

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I had 51-52/2.46 which equaled -0.4065. I am not sure this is the correct answer. It seemed too easy....I also wasn't sure if I needed to find that on the standard normal probability table to complete the question.