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TPE i'ngtiaI/velocity of a 1.79 kg block sliding down a frictionless inclined plane is found to be 1.65 m/s. Then 1.02 5 later, it has
TPE i'ngtiaI/velocity of a 1.79 kg block sliding down a frictionless inclined plane is found to be 1.65 m/s. Then 1.02 5 later, it has a velocity 0 . m s. What is the angle of the plane with respect to the horizontal? Use Newton's second law to determine how the forces acting on the block relate to the net force, which is essentially given. If you need the mass of the block in your final calculation, you have made a mistake somewhere
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