Translate G= News my myucdavis Bookshelf: Verify.. D In the Questions 5-7 we will solve the following problem: You select 15 cards without replacement from a standard deck of 52 cards. What is the probability that you get all 4 aces? D Question 5 0.5 pts First, we need to find the denominator: how many ways are there to pick 15 cards from a standard deck of 52 cards? 0 57! 0 52 X 51 X - . . X 38 O (52 15 0 47! 0 52 x 51 x . . . X 37 D Question 6 1 pts We need to find the numerator, i.e. count in how many ways we can choose 15 cards so that 4 of them are aces.Translate G= News my myucdavis Bookshelf: Verify.. D Question 6 1 pts We need to find the numerator, i.e. count in how many ways we can choose 15 cards so that 4 of them are aces. Note that this means that 4 spots are already taken by 4 aces, and we are only counting number of remaining 15-4=11 cards which can be any cards from remaining 52-4=48 cards. Thus the numerator is 0 59! O 48 0 37! 0 48! 11! 0 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 x 40 x 39 x 38 D Question 7 0.5 pts The answer is O 52 52 15slate News my myucdavis Bookshelf: Verify.. 0 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 x 40 x 39 x 38 D Question 7 0.5 pts The answer is O 17 52 15, 0 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 x 40 x 39 x 38 52! 0 37! 52 15) 0 48 x 47 x 46 x 45 x 44 x 43 x 42 x 41 x 40 x 39 x 38 57! O 48 11 52 15 D In Questions 8-12 we will solve the following problem: Suppose Math 17C has three sections. In section A there are 42 female and 58 male students