Translate the following C code II into MIPS.

const int N = 16;

int A[N] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15};

// C Code II (Using pointers) int* p = A;

int* q = (A+N); int t0 = 0;

for ( ; p!=q;p++) t0 += *p; 

printf (MIPS program 2: The sum is %d , t0);

please comment each instruction.