Translate these loops into C. Assume that the C level integer i is held in register $t1,$s2 holds the c level integer called result, and $s0 holds the base address of the integer MemArray.

addi $t1, $0, 100

loop: lw $s1, 0($s0)

add $s2, $s2, $s1

addi $s0, $s0, 4

addi $t1, $t1, -1

bne $t1, $0, Loop