Treatment of a ketone with $NaB{H}_4$ yields a secondary alcohol. Perhaps surprisingly, treatment of an $-$bromo ketone with $NaB{H}_4$ yields an epoxide rather than a bromoalcohol. Show the structure of the epoxide that would form from treatment of the following compound with $NaB{H}_4.$

You do not have to consider stereochemistry.

You do not have to explicitly draw $H$ atoms.

Do not include lone pairs in your answer. They will not be considered in the grading.