TRUE/FALSE. Write 'T' if the statement is true and 'F' if the statement is false. 1) A 90 percent confidence interval will be wider than a 95 percent confidence interval, ceteris paribus. 1) 2) The Central Limit Theorem says that, if n exceeds 30, the population will be normal. 2) MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 3) The Central Limit Theorem (CLT) implies that: A) the mean follows the same distribution as the population. B) the population will be approximately normal if n 30. C) the distribution of the mean is approximately normal for large n. D) repeated samples must be taken to obtain normality. 3) 4) To estimate the average annual expenses of students on books and class materials, a sample of size 36 is taken. The sample mean is $850 and the sample standard deviation is $54. A 99 percent confidence interval for the population mean is: A) $825.48 to $874.52 B) $826.82 to $873.18 C) $823.72 to $876.28 D) $832.36 to $867.64 4) 5) In constructing a 95 percent confidence interval, if you increase n to 4n, the width of your confidence interval will be (assuming other things remain the same): A) about 25 percent of its former width. B) about four times wider. C) about two times wider. D) about 50 percent of its former width. 5) 6) Concerning confidence intervals, which statement is most nearlycorrect? A) We use the Student's t distribution when is unknown. B) We should use z instead of t when n is large. C) We use the Student's t distribution to narrow the confidence interval. 6)2 SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question. 7) Read the news story below. Using the 95 percent confidence level, what sample size would be needed to estimate the true proportion of stores selling cigarettes to minors with an error of 3 percent? Explain carefully, showing all steps in your reasoning. 7) TRUE/FALSE. Write 'T' if the statement is true and 'F' if the statement is false. 8) The level of significance refers to the probability of making a Type II error. 8) 9) If we desire = .10, then a p-value of .13 would lead us to reject the null hypothesis. 9) 10) For a given Ho and level of significance, if you reject the H0 for a one-tailed test, you would also reject H0 for a two-tailed test. 10) MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 11) Guidelines for the Jolly Blue Giant Health Insurance Company say that the average hospitalization for a triple hernia operation should not exceed 30 hours. A diligent auditor studied records of 16 randomly chosen triple hernia operations at Hackmore Hospital and found a mean hospital stayof 40 hours with a standard deviation of 20 hours. "Aha!" she cried, "the average stay exceeds the guideline." At = .025, the critical value for a right-tailed test of her hypothesis is: A) 2.131 B) 1.960 C) 1.645 D) 1.753 11)3 12) The level of significance is not: A) a value between 0 and 1. B) the chance of accepting a true null hypothesis. C) the probability of a "false rejection." D) the likelihood of rejecting the null hypothesis when it is true. 12) 13) Dullco Manufacturing claims that its alkaline batteries last at least 40 hours on average in a certain type of portable CD player. But tests on a random sample of 18 batteries from a day's large production run showed a mean battery life of 37.8 hours with a standard deviation of 5.4 hours. To test DullCo's hypothesis, the test statistic is: A) -1.980 B) -1.960 C) -1.728 D) -2.101 13) 14) For a sample size of n = 100, and = 10, we want to test the hypothesis H0: = 100. The sample mean is 103. The test statistic is: A) 0.300 B) 3.000 C) 1.645 D) 1.960 14) 15) Which of the following is not a valid null hypothesis? A) H0: 0 B) H0: = 0 C) H0: 0 D) H0: 0 15) 16) John wants to compare two means. His sample statistics were and . Assuming equal variances, the pooled variance is: A) 4.9 B) 3.8 C) 5.1 D) 4.5 16) 17) In a random sample of patient records in Cutter Memorial Hospital, six-month postoperative exams were given in 90 out of 200 prostatectomy patients, while in Paymor Hospital such exams were given in 110 out of 200 cases. In comparing these two proportions, normality of the difference may be assumed because: A) the samples are random, so the proportions are unbiased estimates. B) n 10 and n(1 - ) 10 for each sample taken separately. C) the probability of success can reasonably be assumed constant. D) the populations are large enough to be assumed normal. 17) 18) Management of Melodic Kortholt Company compared absenteeism rates in two plants on the third Monday in November. Of Plant A's 800 employees, 120 were absent. Of Plant B's 1200 employees, 144 were absent. To compare the two proportions, the pooled proportion is: A) .140 B) .130 C) .132 D) .135 18)