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Trying to figure out the formula for p-value and how to find the rejection point for a=0.01? A random sample of 65 restaurant customers was
Trying to figure out the formula for p-value and how to find the rejection point for a=0.01?
A random sample of 65 restaurant customers was taken and they were asked to rate their level of satisfaction with their meal. | ||||||
The restaurant owner claims that the mean satisfaction score exceeds 42. | ||||||
Required: | ||||||
Lettingrepresent the mean satisfaction score for the restaurant, set up the null hypothesisand the alternative hypothesisneeded to provide evidence supporting the claim thatexceeds 42. | ||||||
H0: | 42 | |||||
Ha: | > | 42 | ||||
Using the data contained in tab "Ratings", determine the following: | ||||||
Simple Mean | 42.95384615 | |||||
Assume the population standard deviation is equal to: | 2.64 | |||||
Sample Size | 65 | |||||
z = | 2.912936949 | |||||
p-value: | ||||||
Find the rejection point for = 0.01 | ||||||
Do you reject or not reject the null hypothesis? | Reject |
Ratings |
39 |
45 |
38 |
42 |
42 |
41 |
38 |
42 |
46 |
44 |
40 |
39 |
40 |
42 |
45 |
44 |
42 |
46 |
40 |
47 |
44 |
43 |
45 |
45 |
40 |
46 |
41 |
43 |
39 |
43 |
46 |
45 |
45 |
46 |
43 |
47 |
43 |
41 |
40 |
43 |
44 |
41 |
38 |
43 |
36 |
44 |
44 |
45 |
44 |
46 |
48 |
44 |
41 |
45 |
44 |
44 |
44 |
46 |
39 |
41 |
44 |
42 |
47 |
43 |
45 |
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