TS500 limits maximum deflection at the mid-span of a beam element as "L/360" where L is defined as the clear span length of a beam. And the maximum deflection of a simply supported beam can be calculated by using the following relationship. 8 5wL4 384EI where 8= Maximum deflection W= Magnitude of the distributed load Clear span length of the beam L E = Modulus of elasticity I = Moment of inertia of the cross section = The singly symmetric steel I-section has the following orientation. Determine the magnitude of the maximum allowable distributed load by concerning the deflection limit suggested by TS500. Also, draw the stress profile at the midspan. (E = 2 105 MPa) 150 mm 50 mm -5 mm 12 mm 225 mm 12 mm w =? (kN/m) 5m