Two 180-horsepower water pumps are being considered for installation in a farm. Financial data for these pumps are in the table below. If power cost is a flat 7 cents per kWh over the study period, determine the minimum number of hours of full-load operation per year that would justify the purchase of the more expensive pump at an interest rate of 11% (1 HP = 746 watts = 0.746 kilowatts). Click the icon to view the additional information. Click the icon to view the interest factors for discrete compounding when i = 11% per year. . . . The minimum number of hours of full-load operation required per year to justify the purchase of the more expensive motor is hours. (Round to the nearest whole number.) Get more help - Clear all Check answer e P 4 2 12:59 PM 11/12/2022 17