Two charged spheres, A and C, are placed 5.0 meters apart. Sphere A has a charge of -5.0 x 10-3 C. Sphere C has a charge of -9.0 x 10-3 C. A third sphere, Sphere B, has a charge of +3.0 x 10-3 C. Sphere B is placed between Spheres A and C, such that the net electrostatic force on Sphere B is zero. 5.0 meters ?? A B C qA = -5.0 x 10-3 C qp = +3.0 x 10-3 C q =-9.0 x 10-3 C How far from Sphere A must you place Sphere B so that there is no net electrostatic force on Sphere B?The following diagram shows two Charged spheres arranged to the right of a point in space labelled P. q1zE.T5uC L. : \"'~'~24.5om I \"I"... : 22.01 \"a.\" 18.4om. ;.p I 22ml ,n' I ,e' : ,."24.5cm V one = a.?5po Calculate the magnitude and direction of the net electric field at point P. Summarize your answer, then Show all work. Point P is collinear with a +2.8U MC and a 8.5EI oi: as shown in the following diagram. Point P is 1G cm to the left of the positive charge and 20 cm to the left of the negative charge. What is the electric field at point P? Summarize your answer below, then show all work. Upload work done on separate paper in the drophox. Question 1 N at yet a n 5w ered Ma rked out of 2.06- '-l;' Flag question Question 2 N at yet a n 5w ered Marked out of 2.06 Flag question Question 3 Not yet answered Marked out of 2.00 Flag question Calculate the electric field strength at a distance of 8.25 m from a +6.50 pC charged particle. Answer using the units of ME. I Answerti Calculate the distance from a 5.DC|I pC charged particle at which the electric field strength 12x10? N/C is toward the charge. Answer in units of meters. Answer. What is the charge on a sphere that causes an electric field strength of 5.6 x 107 NIC [towards the charge] measured at a distance of 35 cm from the sphere? Answer in units of Coulombs. Answen