Two charges, Q1= 3.10 UC, and Q2=5.00 UC, are located at points (0,-3.50 cm) and (0,+3.50 cm), as shown in the figure. 2 - 21 What is the magnitude of the electric field at point P, located at (4.50 cm,0), due to Q, alone? Correct, computer gets: 8. 585+06 N/C Hint: The electric field at position P due to charge Q1 is not influenced by charge Q2. Therefore, ignore charge Q2 and apply Coulomb's Law. Remember to convert all units to the SI unit system. 5. [2pt] What is the x-component of the total electric field at P? Correct, computer gets: 1. 775+07 N/C Hint: By the principle of linear superposition, the total electric field at position P is the vector sum of the electric field contribution from charge Q1 and Q2. 5. [2pt] What is the y-component of the total electric field at P? Correct, computer gets: -3. 235+0 7. [2pt] What is the magnitude of the total electric field at P? Correct, computer gets: 1. 805+07 N/C Hint: The electric field at point P is a vector quantity. Review vector addition and recall that Ep = sqrt( Epx^ 2 + Epy^2 ). 8. [2pt] What is the angle (with respect to the x-axis) of the total electric field at point P (use deg as the symbol for degrees)? Answer: Submit All Answers | Last Answer: 38.73^[\\circ } Not yet correct, tries 2/20 9. [2pt] Now let Q2=Q1= 3.10 UC. Note that the problem now has a symmetry that you should exploit in your solution. What is the magnitude of the total electric field at P? Answer:[ Submit All Answers | Last Answer: 8500000 N/C Incorrect, tries 2/20. Hint: Can you say anything about the y-component of the total electric field before you start calculating? 10. [2pt] Given the symmetric situation of the previous problem, what is the magnitude of the force on an electron placed at point P? Correct, computer gets: 2. 176-12 N Hint: Recall what the electric force will be on a charge q in the presence of an electric field E. 11. [2pt] What is the angle (with respect to the x-axis) of the net force acting on an electron placed at point P? Answer: Submit All Answers | Last Answer: 38.73^[\\circ }