Question: Two children are balanced on a seesaw that has a mass of 19.0 kg. The first child has a mass of 26.0 kg and sits

Two children are balanced on a seesaw that has a mass of 19.0 kg. The first child has a mass of 26.0 kg and sits 1.60 m from the pivot. The center of mass of the seesaw is 0.113 m from the pivot (on the side of the first child).

(a) If the second child has a mass of 31.8 kg, how far (in m) is she from the pivot?

(b) What is the supporting force (in N) exerted by the pivot?

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To solve this problem we need to use the principles of rotational equilibrium and static equilibrium We will assume that the seesaw is horizontal and ... View full answer

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