Two identical light bulbs are connected to a battery first in series and then in parallel. Neither of the light bulbs burn out. What is the ratio of the power emitted by each bulb when they are connected in parallel to when they are connected in series?

When light bulbs are connected in series, the same current flows through both bulbs, and the voltage across each bulb is split. Let's denote the resistance of each bulb as [ and the battery voltage as V. When connected in series, each bulb gets 1? voltage across it. The power (P) emitted by a light bulb is given by the formula: r2 R - P = So, when connected in series, the power emitted by each bulb is: series _ _ When light bulbs are connected in parallel, the voltage across each bulb is the same as the battery voltage (1), but the current is split between the bulbs. So, each bulb gets the full voltage V' across it. Thus, the power emitted by each bulb when connected in parallel is: r2 _ Ppamllel R Now, let's find the ratio of the power emitted by each bulb in parallel to when they are connected in series: = 4 .2 parallel T L =4 i = So, the ratio of the power emitted by each bulb when connected in parallel to when they are connected inseriesis4 : 1