Question
Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by 45.0 mm, and the potential difference between them is 360
Two large, parallel, metal plates carry opposite charges of equal magnitude. They are separated by 45.0 mm, and the potential difference between them is 360 V. There is a particle with charge +2.40 nC.
Find the change of potential energy of the particle computed from the electric potential.
Answer:
The charge is moving from a higher potential energy to a lower potential energy, with the change in potential given by U = qV = (2.40 109 C)(360 V) = 8.64 107 J, which is equal to the negative of the work done by the electric force.
My question: How does one know if the charge is moving from a higher potential energy to a lower potential energy (making 360 V negative)?
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