Two moles of a monatomic gas with an rms speed of 254 m/s are contained in a tank that has a volume of 0.15 m3. If each gas particle has a mass of 6.642 10-26 kg, what is the absolute pressure of the gas?

Answer is 1.1 x 10^4 Pa.

From the formulas I was given, I first did m(particle)x 6.022x10^23 = mass per mole. Then, I did mass per mole x n = Mass (which has to be in g?). Then I plugged that into T=v^2M/3R (the M has to be in kg/mol?) Finally, I plugged that in P=nRT/v. I think I may be correct on the way I was setting it up? I am confused as to if I might be converting something wrong or missing a conversion, or am just completely wrong in my set up.Please help me with the work/units. thank you