Two outer energy band structure of a crystal is given by the two following E-k expressions: (ii) (iii) E(k)=- (iv) k ko where Ko = 100 m, = 3 eV, = 1.5 eV and the energy levels up to 4 eV. 2 - B and E(k)= Y k ko 2 = 3.8 ev. At 0 K, the electrons in this crystal can occupy On the graph template provided, draw the two energy bands. Shade the energy levels that will be occupied by electrons at 0 K in this crystal. Identify the Valence Band (VB) and Conduction Band (CB). What is the type of this material? Will this material conduct at 0 K and at 300 K? Find the mass of the electrons in the second energy band (i.e., in the branch E(k)). An electric field is applied to this material at 300 K, and the charge carriers develop a drift velocity of 0.1 cm/s. Find the current through a 1 mm rod made of this material.