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Two plates with area 3.00 x 10-3 m are separated by a distance of 5.90 10-4 m. A charge of 6.40 x 10-8 C
Two plates with area 3.00 x 10-3 m are separated by a distance of 5.90 10-4 m. A charge of 6.40 x 10-8 C is moved from one plate to the other. Assume that the separation distance is small in comparison to the diameter of the plates, and that the charge is uniformly distributed. Calculate the potential difference AV (voltage) between the two plates. AV =
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Chemistry A Molecular Approach
Authors: Nivaldo Tro
5th Edition
0134874374, 978-0134874371
