Two point charges repel each other with a force of 4 x 10-5 newtons at a distance of 1 meter. If the distance is increased to 2 meters, what will the force of repulsion be?

Given:

two conditions (cond.) each containing two repelling point charges.

distance of two point charges for cond. 1 r1= 1m electric force of attraction for cond. 1 Fe1 4 x 10-5 distance of two point charges for cond 2 r2= 2m

Find: Electric Force of repulsion (Fe2), positive value for cond. 2

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