Answered step by step
Verified Expert Solution
Link Copied!

Question

00
1 Approved Answer

Two-Dimensional Kinematics This lab will be performed using the Projectile Motion simulation. Click on the Lab tab at the bottom of the simulation to

image text in transcribedimage text in transcribed

Two-Dimensional Kinematics This lab will be performed using the Projectile Motion simulation. Click on the Lab tab at the bottom of the simulation to be taken to the correct screen to begin. 1. Start with the default cannonball settings when you open the simulation given in row one below. Use the red firing cannon button at the bottom to launch the cannon. Drag the bullseye to the landing site and record the distance the cannonball travelled. Use the yellow eraser to clear the cannonball's path and reload the cannon. Make the given adjustments in each row and fill in the blanks. If needed the orange circular arrow on the bottom right will reset the default settings. Mas S Cannonba Il diameter t (m) Heigh (kg) Gravity (m/s) Initial Angle speed (m) (m/s) Distanc e (m) Defaul 17.6 0.18 0 9.81 t 0 60 18 80 11.3m Trial 1 31.0 0.18 0 9.81 80 0 60 18 11.3m Trial 2 17.6 1.00 0 9.81 0 60 18 80 11.3m Trial 3 17.6 0.18 2 18 9.81 80 11.7m 0 Trial 4 17.6 0.18 0 0 9.81 60 60 18 28.7m Trial 5 17.6 0.18 0 0 25 9.81 80 21.8m 2. Based on your results above, what impact does the mass or diameter of the item launched have on the distance travelled. Explain your response. 3. Why would changing the height of the launch change the distance the cannonball travels? 4. Calculate the launch velocity needed to successfully land the cannon ball at each distance, given the following conditions: launch angle (9) was 27.5, the launch height (yi) was 9.59 m, the height of the landing pad (y) was 2.50 m, and the range (R) is the cannon-landing site distance. V = R g cos(0) 2[R tan(0) - (yf - y;)] Cannon- landing site Launch Velocity (m/s) distance (m) 68 ~22.9 m/s 75 245 ~26.64 m/s ~61.1m/s 5. Suppose that the experiment was performed with a cannonball launched at an initial velocity of 30 m/s. What is the distance (R) to the landing site? Note that the launch angle (9) was 27.5, the launch height (yi) was 9.59 m, and the height of the landing site (y+) was 2.50 m. v sin(0) + v sin (0) + 2g(y; y) - R = vi cos(0) g ~86.27m 6. On Jupiter, the gravitational acceleration (g) is equal to 24.8 m/s. Suppose that the experiment was performed on Jupiter, using a distance (R) of 68 m from the cannon to the landing site. What velocity would you need to shoot the cannonball to the landing site? Note that the launch angle (9) was 27.5, the launch height (yi) was 9.59 m, and the height of the landing site (yf) was 2.50 ml. R V = g cos(0) 2[R tan(0) - (yf - y;)] ~65.6m/s

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access with AI-Powered Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Fundamental Managerial Accounting Concepts

Authors: Thomas Edmonds, Christopher Edmonds, Bor Yi Tsay, Philip Olds

8th edition

978-1259569197

Students also viewed these Physics questions