Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Type of Collision Elasticity Super-elastic k = 1 Elastic k =1 Inelastic k > reset Time: 0 m = +2 m = +2 V =

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
Type of Collision Elasticity Super-elastic k = 1 Elastic k =1 Inelastic k > reset Time: 0 m = +2 m = +2 V = +0 Elastic: Im1=m2 m1=5m2 4.00 Momentum vs. Time 5m1=m2 P 2.00 k=0.5: m1=m2 m1=5m2 0.00 -1.00 0.00 1.00 5m1=m2 1=0.0; 4.00 Kinetic Energy vs. Time m1=m2 m1=5m2 M 2.00 5m1=m2 0.00 E -1.00 0.00 1.00Type of Collision Elasticity Super-elastic k> 1 2 Elastic k =1 Inelastic k > reset Time: 0.76 m = +2 m = +2 V = +0.5 = +1.5 Elastic: m1=m2 m1=5m2 4.00 Momentum vs. Time 5m1=m2 P. 2.00 k=0.5: m1=m2 m1=5m2 0.00 0.00 0.50 1.00 5m1=m2 k=0.0; 4.00- Kinetic Energy vs Time m1=m2 m1=5m2 14 2.00 5m1=m2 0.00 0.00 0.50 1.00Type of Collision Elasticity Super-elastic k= 1 3 Elastic k =1 Inelastic k > reset Time: 1.52 m=- m = +2 +0 V = +2 Elastic: |m1=m2 m1=5m2 4.00 Momentum vs. Time 5m1=m2 P 2.00 k=0.5: m1=m2 m1=5m2 0.00 0.00 0.50 1.00 1.50 5m 1=m2 t k=0.0 4.00 Kinetic Energy vs. Time |m1=m2 m1=5m2 14 2.00 5m1=m2 0.00 0.00 0.50 1.00 1.50 tType of Collision Elasticity Super-elastic k= 1 Elastic k =1 Inelastic k > reset Time: 0 m = +2 m = +0.4 V= 12 V = +0 Elastic: m1=m2 m1=5m2 4.00 Momentum vs. Time 5m1=m2 P 2.00 k=0.5: m1=m2 m1=5m2 0.00 -1.00 0.00 1.00 5m1=m2 k=0.0: 4.00 Kinetic Energy vs. Time m1=m2 m1=5m2 1 2.00 5m 1=m2 0.00 -1.00 0.00 1.00\fType of Collision Elasticity Super-elastic k= 1 Elastic k =1 3 Inelastic k > reset Time: 1.5 m = +2 m = +0.4 V = +1.667 v = +1.667 Elastic: m1=m2 m1=5m2 4.00 - Momentum vs. Time 5m 1=m2 P 2.00 k=0.5: m1=m2 m1=5m2 0.00 0.00 0.50 1.00 1.50 5m 1=m2 t k=0.0: 4.00 - Kinetic Energy vs. Time m1=m2 m1=5m2 14 2.00 5m1=m2 0.00 0.00 0.50 1.00 1.50Type of Collision Elasticity Super-elastic k > 1 Elastic k = 1 Inelastic k > reset Time: 0 m = +0.4 m = +2 V= +2 V = +0 Elastic: m1=m2 x10 3 m1=5m2 Momentum vs. Time 5m1=m2 500.00 k=0.5: m1=m2 m1=5m2 0.00 -1.00 0.00 1.00 5m 1=m2 k=0.0: x10-3 Kinetic Energy vs. Time m1=m2 m1=5m2 500.00 5m1=m2 0.00 -1.00 0.00 1.00

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Elements Of Chemical Reaction Engineering

Authors: H. Fogler

6th Edition

013548622X, 978-0135486221

Students also viewed these Physics questions