Under certain waterconditions, the free chlorine(hypochlorous acid,HOCl) in a swimming pool decomposes according to the law of uninhibited decay. After shocking apool, the poolboy, Geoff, tested the water and found the amount of free chlorine to be 2.8

2.8 parts per million(ppm). Twenty-four hourslater, Geoff tested the water again and found the amount of free chlorine to be 2.5

2.5 ppm. What will be the reading after 4

4 days(that is, 96

96 hours)? When the chlorine level reaches 1.0ppm, Geoff must shock the pool again. How long can Geoff go before he must shock the poolagain?

After 4

4 days, or 96

96 hours, the amount of free chlorine in the pool will be

nothing

ppm.

(Do not round until the final answer. Then round to the nearest hundredth asneeded.)