Unsure of how to solve this LP. Show all work please, thanks!

Solve the following LP using the two-phase simplex method. maximize 4.61 + 12 subject to - + 2x2 0 The tableaux below assume maximization objective; so in case of a minimization problem, convert it to maximization Use the Bland's rule to select the entering and leaving variable at each step. If you think that some field should be left blank, put the dash (-) in that field. Some examples: if phase II is not needed, fill in all the blank fields in the phase II tableaux with dashes. If the problem is infeasible or unbounded, put dash in the cells asking for optimal solution. Phase! Step 0 Tableau and the first step's ratio test: z x1 x2 151 e3 la2 a3 rhs BV Ratio 1 lo 10 -5 IZ 10 0 10 s1 10 lo 0 11 10 0 11 lo Step 1 Tableau and the second step's ratio test: Iz 51 le 3 a2 a3 rhs BV Ratio x1 0 1 10 0 Z Is 1 O 10 0 0 | 1 0 lo 0 JO 1 1 1 Step 2 Tableau z X1 X2 Is 1 le 3 a2 a3 rhs BV 1 N 0 10 1 s1 0 10 0 11 lo lo 1 10 Is this LP feasible? (type yes or no) Phase II Step 0 Tableau and the first step's ratio test: IZ x1 s1 e3 rhs BV Ratio 1 10 0 s1 0 0 | 1 0 0 10 1 10 Step 1 Tableau z x1 151 e3 Irhs BV 1 0 0 10 110 1 0 1 Is this LP optimal? (type yes or no) The optimal solution is: x1=1 Solve the following LP using the two-phase simplex method. maximize 4.61 + 12 subject to - + 2x2 0 The tableaux below assume maximization objective; so in case of a minimization problem, convert it to maximization Use the Bland's rule to select the entering and leaving variable at each step. If you think that some field should be left blank, put the dash (-) in that field. Some examples: if phase II is not needed, fill in all the blank fields in the phase II tableaux with dashes. If the problem is infeasible or unbounded, put dash in the cells asking for optimal solution. Phase! Step 0 Tableau and the first step's ratio test: z x1 x2 151 e3 la2 a3 rhs BV Ratio 1 lo 10 -5 IZ 10 0 10 s1 10 lo 0 11 10 0 11 lo Step 1 Tableau and the second step's ratio test: Iz 51 le 3 a2 a3 rhs BV Ratio x1 0 1 10 0 Z Is 1 O 10 0 0 | 1 0 lo 0 JO 1 1 1 Step 2 Tableau z X1 X2 Is 1 le 3 a2 a3 rhs BV 1 N 0 10 1 s1 0 10 0 11 lo lo 1 10 Is this LP feasible? (type yes or no) Phase II Step 0 Tableau and the first step's ratio test: IZ x1 s1 e3 rhs BV Ratio 1 10 0 s1 0 0 | 1 0 0 10 1 10 Step 1 Tableau z x1 151 e3 Irhs BV 1 0 0 10 110 1 0 1 Is this LP optimal? (type yes or no) The optimal solution is: x1=1